33 lines
1.1 KiB
Python
33 lines
1.1 KiB
Python
# 突然放量策略
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import numpy as np
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import datasource,time, dingding
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def stratergy_run(symbol, interval, df, debug):
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# 计算过去 30 根 K 线的平均交易量
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average_volume = df["volume"].iloc[-31:-1].mean() # 倒数第 31 到倒数第 2 根的平均
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# 获取当前（最后一根，即第 500 根）交易量
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current_volume = df["volume"].iloc[-1]
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timestamp = df['timestamp'].iloc[-1]
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rate = current_volume / average_volume
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if rate > 10:
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message = "📢Signals Notificaiton📢\r\n\r\n"
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message += f"{symbol} 在 {interval} 出现放量 {round(rate, 2)}倍 ！\r\n\r\n"
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message += f"{timestamp}"
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if debug == False:
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dingding.send_message(message, True)
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print(f"【{symbol} - {interval}】 is singal fired!")
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else:
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print(message)
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def run_crypto(interval, debug=False):
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symbols = datasource.crypto.get_future_symbols()
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for s in symbols:
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df = datasource.crypto.get_klines(s, interval, True,limit=50)
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stratergy_run(s,interval, df, debug)
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time.sleep(1) |